Assignment Answers Key - Statistical Methods | STA 2023, Assignments of Data Analysis & Statistical Methods

Material Type: Assignment; Professor: Murphy; Class: Statistical Methods; Subject: STA: Statistics; University: Valencia Community College; Term: Unknown 2009;

Typology: Assignments

Pre 2010

Uploaded on 08/03/2009

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EXERCISES:
KEY
1. Suppose medical researchers think that 0.70 is the proportion of all teenagers with high blood
pressure whose blood pressure would decrease if they took calcium supplements. To test this
theory, the researchers plan a clinical trial (experiment) in which 200 random teenagers with high
blood pressure will take regular calcium supplements.
a. Assume 0.70 actually is the population proportion that would experience a decrease in
blood pressure. What are the numerical values of the mean and standard deviation of the
sampling distribution of the sample proportions for samples of 200 teenagers?
(
)
70.0
ˆ== pp
µ
( )
(
)
(
)
0324.0
200
30.070.01
ˆ=
=n
pp
pSD
p
ˆ
.603 .635 .668 .7 .732 .765 .797
b. Use the results of part (a) to calculate an interval that will contain the sample proportion
for about 99.7% of all samples of 200 teenagers.
By the Empirical Rule and part (a) we have (0.603, 0.797).
c. In the clinical trial, 120 of the 200 teenagers taking calcium supplements experienced a
decrease in blood pressure. What is the value of
p
ˆ
for this sample? Is this value a
parameter or a statistic?
60.0
200
120
ˆ==p Statistic.
d. What is the probability of having 120 or fewer experience a decrease of blood pressure
out of a sample of 200 teenagers taking calcium supplements?
normalcdf(-1E99, 0.60, 0.70, 0.0324) = 0.001 or 0.1%
e. We have used the properties of a normal distribution. Show that the
conditions/requirements are satisfied.
1. The selection was an SRS as indicated by “200 random
teenagers.”
2.
10140)7.0(200
=
=
np
3.
(
)
(
)
10603.02001 == pn
4.
2000)200(1010
=
=
n
There are at least 2000 teenagers with high blood pressure.
pf2

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EXERCISES : KEY

  1. Suppose medical researchers think that 0.70 is the proportion of all teenagers with high blood

pressure whose blood pressure would decrease if they took calcium supplements. To test this

theory, the researchers plan a clinical trial (experiment) in which 200 random teenagers with high

blood pressure will take regular calcium supplements.

a. Assume 0.70 actually is the population proportion that would experience a decrease in

blood pressure. What are the numerical values of the mean and standard deviation of the

sampling distribution of the sample proportions for samples of 200 teenagers?

μ ( p ˆ ) = p = 0. 70

n

p p SDp

p ˆ

b. Use the results of part (a) to calculate an interval that will contain the sample proportion

for about 99.7% of all samples of 200 teenagers.

By the Empirical Rule and part (a) we have (0.603, 0.797).

c. In the clinical trial, 120 of the 200 teenagers taking calcium supplements experienced a

decrease in blood pressure. What is the value of p ˆ for this sample? Is this value a

parameter or a statistic?

p ˆ^ = = Statistic.

d. What is the probability of having 120 or fewer experience a decrease of blood pressure

out of a sample of 200 teenagers taking calcium supplements?

normalcdf(-1E99, 0.60, 0.70, 0.0324) = 0.001 or 0.1%

e. We have used the properties of a normal distribution. Show that the

conditions/requirements are satisfied.

  1. The selection was an SRS as indicated by “200 random

teenagers.”

  1. (^) np = 200 ( 0. 7 )= 140 ≥ 10

3. n ( 1 − p ) = 200 ( 0. 3 ) = 60 ≥ 10

  1. 10 n = 10 ( 200 )= 2000

There are at least 2000 teenagers with high blood pressure.

  1. DO YOU DRINK THE CEREAL MILK? A USA Today poll asked a random sample of 1012

U.S. adults what they do with the milk in the bowl after they have eaten the cereal. Of the

respondents, 67% said that they drink it. Suppose that 70% of U.S. adults actually drink the cereal

milk.

a. Explain why you are allowed to use the formulas for normal distributions of sample

proportions.

  1. The selection was an SRS as indicated by “a random sample of

1012 U.S. adults.”

  1. np = 1012 ( 0. 7 )= 708. 4 ≥ 10

3. n ( 1 − p ) = 1012 ( 0. 3 ) = 303. 6 ≥ 10

  1. 10 n = 10 ( 1012 )= 10 , 120

There are at least 10,120 U.S. adults that eat cereal.

μ ( p ˆ^ ) = p = 0. 70

n

p p SDp

p ˆ

b. Find the probability of obtaining a sample of 1012 adults in which 67% or more say they

drink the cereal milk.

normalcdf(0.67, 1E99, 0.7, 0.0144) = 0.9814 or 98.14%

c. What proportion would say that they drink the cereal milk if it is in the lower 20% of all

samples of 1012 U.S. adults?

InvNorm(0.20, 0.7, 0.0144) = 0.6879 or less

In other words, regarding samples in the lower 20% of the sampling

distribution, 68.79% or less of the sample of 1012 adults would say that

they drink the cereal milk

d. What is the z-score for a sample of 1012 U.S. adults in which 75% of them said that they

drink the cereal milk?

n

p p

p p z