Conservation of Energy and Motion in Classical Mechanics, Exercises of Classical and Relativistic Mechanics

The concept of conservation of energy in classical mechanics and its application to solve problems of particle motion. It covers the relationship between potential energy, force, and motion, as well as the concept of conserved angular momentum in central forces. The document also discusses the conservation of energy and angular momentum in polar coordinates.

Typology: Exercises

2011/2012

Uploaded on 07/19/2012

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1 Conservation of Energy
Today we will talk about what conservation of energy is good for how it can help us solve problems
in classical mechanics. If we have a particle q:RRnsatisfying F=ma where Fis conservative:
F(t) = V(q(t))
where V:RnRis called the potential, then energy is conserved. Let
E(t) = 1
2m˙q(t)2+V(q(t)).
Then
d
dt E(t) = m˙q(t)·¨q(t) + V(q(t)) ·˙q(t)
=F(q(t)) ·˙q(t) + V(q(t)) ·˙q(t)
= 0
What good is this? It helps understand the motion of the particle: for any solution of Newton’s
second law 1
2m˙q(t)2+V(q(t)) + E
|| ˙q(t)|| =r2
m(EV(q(t)))
so we know the particle’s speed given its position. This is especially powerful for a particle on the
line (n=1).
Example: A particle on a line. In this case, suppose the force depends only on position:
F(t) = f(q(t))
for f:RR. Then automatically Fis conservative:
f=−∇V
=dV
dx
where
V(x) = Zx
x0
f(s)ds.
Note: we can add any constant to V. Also: the fact that any fis −∇Vfor some Vis special to 1
dimension.
So we have:
|˙q(t)|=r2
m(EV(q(t)))
1
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1 Conservation of Energy

Today we will talk about what conservation of energy is good for — how it can help us solve problems in classical mechanics. If we have a particle q: R → Rn^ satisfying F = ma where F is conservative:

F (t) = − ∇V (q(t))

where V : Rn^ → R is called the potential, then energy is conserved. Let

E(t) =

m q˙(t)^2 + V (q(t)).

Then

d dt E(t) = m q˙(t) · ¨q(t) + ∇V (q(t)) · q˙(t) = F (q(t)) · q˙(t) + ∇V (q(t)) · q˙(t) = 0

What good is this? It helps understand the motion of the particle: for any solution of Newton’s second law 1 2

m q˙(t)^2 + V (q(t)) + E

|| q˙(t) || =

m

(E − V (q(t)))

so we know the particle’s speed given its position. This is especially powerful for a particle on the line (n=1).

Example: A particle on a line. In this case, suppose the force depends only on position:

F (t) = f (q(t))

for f : R → R. Then automatically F is conservative:

f = −∇V

= −

dV dx

where

V (x) =

∫ (^) x

x 0

f (s)ds.

Note: we can add any constant to V. Also: the fact that any f is −∇V for some V is special to 1 dimension. So we have:

| q˙(t) | =

m

(E − V (q(t)))

so

q˙(t) = ±

m

(E − V (q(t)))

For example:

graph of some f unction V (x) on plane with chosen energy value V = E

The particle’s position, say x, must have

V (x) ≤ E.

This is called the classically allowed region - in our example, [x 0 , x 1 ]. The set of x ∈ R where V (x) > E is the classically forbidden. A particle at a local maximum can go one of the two possible directions. If the potential increases all the way up to V = E, the particle stops for moment and then Newton’s second law demands that the particle goes back down the graph. In our example the particle must oscillate between x 0 and x 1 , moving faster where V is smaller.

Example: A particle in R^3 in a central force.

picture of a central f orce f ield

A central force depends only on position, so it’s given by f : R^3 − { 0 } → R^3 , but where f is spherically symmetric:

f (x) = φ(|| x ||)

x || x ||

where φ: [0, ∞) → R. (We’ll worry about the origin in R^3 when necessary.) We’ll write

|| q(t) || = r(t)

q(t) || q(t) || = rˆ(t)

so Newton’s 2nd law says mq¨(t) = φ(r(t))ˆr(t).

Kepler started thinking about planetary motion - this is motion in a central force

φ(r) = −

k r^2

He noted that planets sweep out equal area in equal time:

picture of planet going around sun with area f rom t 0 to t 0 + ∆t and f rom t 1 to t 1 + ∆t

This is secretly “conservation of angular momentum”. This will let us understand motion in any central force. First, a central force is automatically conservative: if

f (x) = φ(|| x ||)ˆx, (ˆx =

x || x ||

then f (x) = − ∇V (x)

where V (x) = v(|| x ||)