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Curvilinear Plan Projectile Solved Problems, Exercises of Electrical Engineering

This is solution to problems related Electrical Engineering course. It was suggested by Prof. Bhooshan Sawhney at Shree Ram Swarup College of Engineering and Management. It includes: Coordinate, Current, Flux, Magnetic, Field, Maximum, Result, Electric, Lines, Loop, Direction

Typology: Exercises

2011/2012

Uploaded on 07/20/2012

apurva
apurva 🇮🇳

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Download Curvilinear Plan Projectile Solved Problems and more Exercises Electrical Engineering in PDF only on Docsity!

2/5] y= + = 203) - 008) _ si- 2.6) 2 0.02 ue lufe yf is3e25" = 2.92 mls - % ~ =2.5 5 ge . tan @ = = eT Es , Be -St0 AU s. 2 eo = 23K = 2/00 | Day AE a= lan{=y 3 _5_mjs* teres - + ) OF sai 2/él = ot Sav at Ac+ejy = Ty Va gg Couak + S2ayy] /oo2 VEU = SRL S.3ej mls wa copa = va Ur a 6.207 73.36" = 7.05 mis a=V47ee* = 12) mis® (6.20. +330j)- (4. ey A5.0 6 - 30. cos 05) (1.2 5a OF es 211° afo2| y= 2yr-4t y= stat} we abe gr ete q = 4 mms? 4 = 67 2t At te ay § = G2)-2* = F mms vedere? = VFR eP = 8.14 mols Oy = tea = ten’ Et 64? Ab te As: i 4+ mm|st 4 = &-2(z) = Zmm|s™ = VAR 2 = FAT mms 4* @,- tan 2 = tan B= 260° x Qe Re “A docsity.com