Module 6.03 - Honors Lab, Exercises of Chemistry

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Calorimetry: Lab Report
Part I: The Dissolving of Solid Sodium Hydroxide in Water
Procedure:
1. Measure out approximately 205 mL of distilled water and pour it into the calorimeter. Stir
carefully with a thermometer until a constant temperature is reached. Record the volume of
water and the constant initial temperature of the water on your data table.
2. Place a plastic measuring trough on top of the digital balance, and then zero the balance
(press the tare button) so that the mass of the trough will be "ignored" and will not be added
to the total mass measured by the balance.
3. Measure out approximately three to five scoops of solid sodium hydroxide and record the
mass to your data table.
4. Place the solid sodium hydroxide into the water in the calorimeter and replace the lid
immediately. Stir gently until the solid is completely dissolved and record the highest
temperature reached.
Data and Observations:
Calculations:
Equation for Chemical Reaction
NaOH (s) +H2O (l) —> NaOH (aq)
Number of moles of NaOH dissolved in the water
2.535 g NaOH * 1 mol NaOH / 39.997 g NaOH = 0.06338 mol NaOH
Calculating the amount of energy involved in this dissolving process.
-qNaOH = m × c × ΔT = 200 mL * 1g/1L * 4.184 J / (g × °C) * (27.8-24.2) °C = 3012.5 J
Determining the enthalpy change, per mole of sodium hydroxide dissolved
3012.5 J / 0.06338 mol NaOH = -475307 J * 1 kJ/1000 J = -47.53 kJ
Volume of Water
200.0 mL H2O
Mass of NaOH
2.535 g NaOH
Initial Temperature in Calorimeter
24.2 C
Final Temperature in Calorimeter
27.8 C
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Calorimetry: Lab Report

Part I: The Dissolving of Solid Sodium Hydroxide in Water Procedure:

  1. Measure out approximately 205 mL of distilled water and pour it into the calorimeter. Stir carefully with a thermometer until a constant temperature is reached. Record the volume of water and the constant initial temperature of the water on your data table.
  2. Place a plastic measuring trough on top of the digital balance, and then zero the balance (press the tare button) so that the mass of the trough will be "ignored" and will not be added to the total mass measured by the balance.
  3. Measure out approximately three to five scoops of solid sodium hydroxide and record the mass to your data table.
  4. Place the solid sodium hydroxide into the water in the calorimeter and replace the lid immediately. Stir gently until the solid is completely dissolved and record the highest temperature reached. Data and Observations: Calculations: Equation for Chemical Reaction NaOH (s) +H2O (l) —> NaOH (aq) Number of moles of NaOH dissolved in the water 2.535 g NaOH * 1 mol NaOH / 39.997 g NaOH = 0.06338 mol NaOH Calculating the amount of energy involved in this dissolving process. -qNaOH = m × c × ΔT = 200 mL * 1g/1L * 4.184 J / (g × °C) * (27.8-24.2) °C = 3012.5 J Determining the enthalpy change, per mole of sodium hydroxide dissolved 3012.5 J / 0.06338 mol NaOH = -475307 J * 1 kJ/1000 J = -47.53 kJ Volume of Water 200.0 mL H2O Mass of NaOH 2.535 g NaOH Initial Temperature in Calorimeter 24.2 C Final Temperature in Calorimeter 27.8 C

Part II: The Reaction of Sodium Hydroxide Solution with Hydrochloric Acid Procedure:

  1. Measure out approximately 100 mL of 0.50 M hydrochloric acid solution and 100 mL of 0. M sodium hydroxide solution. Record both volumes on your data table.
  2. Pour the hydrochloric acid solution into the calorimeter. Measure and record the initial temperature of each solution and record on your data table.
  3. Add the sodium hydroxide solution to the acid solution in the calorimeter and immediately replace the lid of the calorimeter. Stir the mixture and record the highest temperature reached. Data and Observations: Calculations: Balanced equation for the reaction HCl (aq) + NaOH (s) —> NaCl (aq) +H2O (l) Determining the enthalpy change of this reaction q = (200.5 mL * 1g/1mL) * 4.184 J / (g × °C) * (28.2 - 25.2)°C = 2516.7 J Determine the number of moles of NaOH 100 mL * 1 L/ 1000 mL 1g/1mL * 0.5 mol NaOH/ 1 L NaOH * = 0.050 mol NaOH Determine enthalpy per mole of NaOH. Show all of your work. 2516.7 J / 0.050 mol NaOH = 50334 J/mol * 1 kJ/ 1000 J = 50.3 kJ Conclusion: Determine the enthalpy change for NaOH (s) + HCl (aq) → NaCl (aq) + H2O (l) using Hess's Law. a. Write the balanced chemical reaction and enthalpy change for Part I (1pt) NaOH (s) +H2O (l) —> NaOH (aq); q = -30.1 kJ Volume of HCl Solution 100.5 mL HCl Volume of NaOH Solution 100.0 mL NaOH Initial Temperature in Calorimeter 25.2 C Final Temperature in Calorimeter 28.2 C