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Mathematics of Shobhit nirwan Maha marathron
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*[Aim l00/^100 in^ Mathsl
Two positve Integens m and n ate p? and^ n^ pg^ ,^ whene^ p and q aMe prnime numbeHS. The LCM of m and
expHessed
h is
b: 2y 35
LCM = 3180 , then iS
C : ax 37
LCM &x3X5x
3480 z 4637 35 3780 140x
.b 2x3x5C^ =ax^ 3xt eaual to
3 |
3 [Compang
ohene
Lcu (p,4) is :
amd
a
LCM ax
) The
ax 62
HCE of (^) p (^) and q?
p = 18a?b
then
> (^) at (^) be a, (^) amd ax (^) be p
qMe natunal
The Smallest
are pri me^ mbe^ g,^ hen
and 4 = 20qa
numbens and
is the HCF of p and.
LCM of the Smallest odd prime nwmbeH and gHeatat &- digit num ber
pnime number (e 3
is 13 ,^ F^ LCM^ i6^ 40.^ Find^ the^ value^ ofX LCM X HCF= Product of a no
of too numbens 65 and 104
LCM = Product of a number
40 - 68 x|
40X (^) 5 X 104
and la 49, Ieaving HESpecfively is :
(a
HCE
821-5 a
&
(a49 -t 1a
69
umbeh ohich^ divides^081 Hemain dem 5 and
HCF -ax 3x HCE = 132 o 138 is^ the
(^9) Can (^) the num (^) bet (^) (16)", n (^) betng natunal number end with the digt 0? Grive The HeaSonS. w0s (Is)" -(axs) prime factotizahon of (151" hos the pntme facto 5 but not the (^) prtime factor 2.Yf^ n end with digit 0 then it needs the prtime Factor 2 and 5.
numbet m. D) Chech 0 fom any ohether ()" can end with the digtt naturn a numberr n. (a) =(3x3)n no The (^) prime facto nigation of (4)" has hel prime factos 5 and 2. X (4) has to end witth dgit o then needs he ptime facton a amd
hatural (^) nwmben n.
together after ohot tfme wnl they next toll q: 3X Given GÉ (^) ve n (^) values t (^) siT (^) Ang - HCF 15 *3 5 LCM - a 3 Q LCM - 180 minuteg -. they will next 3
55 a0= 2'x 4a (^) seCo (^) nds (^) and Two alarm dock Hing their alanns at Heguar in*nvals oh a0 (^) min utes & (^) a5 (^) mintes they wll^ beep^ again^ togethen^ after^ l min Utes.
beep together at 2 noon, at
L) (^) Xn a (^) ftatee] (^) teachens' (^) okshop the (^) number of (^) kacheHS taching (^) Frunch, (^) Hindi (^) and Engteh ake^ 48, (^80) aund (^144) HeSpectivey: find (^) tha (^) minimum (^) numer o
nequitied (^10) ach (^) noom (^) the (^) 3ame
48 - a1y
6 3
aro seated and thum (^) ave (^) of (^) the (^) some (^) ubject. Q
36
HOoMS MQuited.
hunso s teachers
cin aulan (^) path crnoumd a Spots (^) keld. (^) Sonia (^) takes (^18) munutis to dye on (^) howmd f (^) the (^) feld, (^) ohile Raui (^) tabs 1a (^) munua (^) for (^) ha (^) Same. both (^) stat at he (^) 5ome p&Umt Omd at the ome ime and go
mamy minues will they mt again at
the
took
18
a
TS) Prove Tumber
that &- (^) Ja6 o (^) an (^) iHhaiona
nume. ) At (^) a-3 be (^) Hafional
5
unce
5
5p + 24 i6 a national
a-
a-3 - 5p
5
is a^ national^ numse^ shich^ contadics the Foact^ that^3 is^ un^ itationd^ umben.
amd 0-primes Qnd^ +0^ J
B 5p t2/
am îMatio^ nal^ numl
an iMmationallser.
fact that^5 S an^ nal
a Hotionolnms which Con -tra
5 P-
umen
-3 5 =
0- Primes^ omd
t-^35 = P pwhee^ qomd
Hatiomal
umler.
-2/5is on Thhohonal that^5 is an itnafionaln
. 5 is
’fet be7-
that.
thum,
gien
Prove
13 (5x 11t3) >*5) 11 88
Composite um.
Betng (^) health (^) Conscious , (^) she (^) decded to (^) serve
Most?
momy gests
get?
CO mpesik numban.
Khushi (^) Cam (^) invite at (^) the
Paeh guest
tnay (^) 9uests (^) Khushi con (^) in (^) vite at (^) the
ho O most?
60
Q| a 3
[..
3
= 12|
a a 30 315
