Stability Analysis of Steady States for Differential Equations, Exams of Building Materials and Systems

The concept of steady states or equilibria in differential equations of the form x'(t) = f(x), and the methods to determine their stability using graphical and linear analysis. The document also provides an example of a chemical reaction model and its steady states analysis.

Typology: Exams

2021/2022

Uploaded on 09/07/2022

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Steady states
Steady states [equilibria, fixed points] for the differ-
ential equation of the form
x0(t) = f(x)
are those values of xthat satisfy f(x) = 0.
Question of interest: what is the stability of such
steady states? If xis perturbed from its steady state
value x, does it return to xor move away from x?
Stability analysis
For equations of the form x0(t) = f(x), there are two
approaches to determine the stability of fixed points:
Graphical stability analysis
Linear stability analysis
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pf4
pf5

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Steady states

Steady states [equilibria, fixed points] for the differ- ential equation of the form

x′(t) = f (x) are those values of x that satisfy f (x) = 0.

Question of interest: what is the stability of such steady states? If x is perturbed from its steady state value x∗, does it return to x∗^ or move away from x∗?

Stability analysis

For equations of the form x′(t) = f (x), there are two approaches to determine the stability of fixed points:

  • Graphical stability analysis
  • Linear stability analysis

Graphical stability analysis for the cooling

problem with equation x′(t) = k(21 − x)

Boardwork...

Graphical stability analysis for the general

problem with equation x′(t) = f (x)

Boardwork...

Graphical stability analysis: observations

We note the following relationship between the sta- bility of a fixed point x∗^ of the differential equation x′(t) = f (x) and the slope of f (x):

  • If f ′(x∗) > 0, then x∗^ is unstable
  • If f ′(x∗) < 0, then x∗^ is stable

Linear stability analysis

We are considering

dx dt

= f (x) (1)

with steady state x∗, that is, f (x∗) = 0.

Introduce a small perturbation y from x∗, that is, let

x = x∗^ + y (2)

Substitute (2) into (1), and expand the right-hand- side with a Taylor series to get:

d(x∗^ + y) dt

= f (x∗^ + y) dy dt

= f (x∗) + f ′(x∗)y + O(y^2 )

Since x∗^ is a fixed point, we can replace f (x∗) on the right hand side by 0. If, in addition, we can safely neglect all the terms in the Taylor series that have been collected in the term O(y^2 ), then we are left with the following equation for the perturbation:

dy dt

= f ′(x∗)y.

We recognize that f ′(x∗) is some constant, λ say. The equation for the perturbation thus is the linear equa- tion dy dt

= λy, which we studied previously (the world’s simplest dif- ferential equation).

The solution for this last differential equation is y(t) = y 0 eλt.

  • If λ < 0, then y(t) → 0 as t → ∞.
  • If λ > 0, then y(t) → ±∞ as t → ∞.

That is, the perturbation dies out if λ = f ′(x∗) < 0, and grows if λ = f ′(x∗) > 0. In the special case that λ = f ′(x∗) = 0, the terms collected in the term O(y^2 ) become important, and other techniques of analysis are required. The theorem presented earlier follows.