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Solutions to five case problems on maximizing profit in production under given demand functions, cost functions, and production functions. The problems involve monopolistic producers of various goods and require finding the optimal production quantities and prices to achieve maximum profit.
Tipo: Apuntes
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CONSTRAINED OPTIMIZATION: Lagrange multipliers Case problems
1. A monopolistic producer of two goods A and B faces the following demand functions: Q A= 50 - PA - QB and Q B= 25 – 0.25 PB – 0.25 QA , where QA and QB denote amounts of production for A and B, and PA and PB - their prices respectively. The constant cost of production amounts to $70. Production of every unit of A demands additional cost of $5, and every unit of B – additional cost of $10. a) What maximum profit can be achieved under these conditions? What amounts of A and B goods shall be produced then? Answer: QA=15, QB=7.5 Π= $ b) Say, company intends to spend just $170 on production of A and B. What maximum profit can be achieved then? Answer: Q͞A=10, Q͞B =5 Π* = $530, and λ= c) What approximate increase in profit could expect producer in the latter case if additional $2 were allocated for A and B production? Answer: Since λ=3 and ΔΠ≈ λ x ΔM, ΔΠ≈ 3 x 2= $ 2. A monopolistic producer of two goods X1 and X2 has the following joint cost function: C= 10(Q 1 +Q 2 )+Q 1 Q 2 , where Q 1 and Q 2 denote the quantities of the X1 and X respectively. The demand functions for these two goods are identified as P 1 = 50 - Q 1 + Q 2 and P 2 = 30 + 2Q 1 - Q 2. The firm has been contracted to produce a total amount of 15 goods of either type. What would be the optimal production quantities of each good? Answer: Q* 1 =10, Q* 2 =5, and λ= If the production quota is raised by 2 units, what profit increase it would entail? Answer: Since λ=30 and ΔM=+2, ΔΠ≈ 30x 2= 60 3. A firm which manufactures speciality bicycles has the following profit function Π = 5X^2 + 3Y^2 - 10XY +240X , where X denotes the number of frames and Y denotes the number of wheels. Find the profit maximizing number of bicycles, assuming that this firm does not want any spare parts (frames or wheels) left at the end of the production run. Answer: X =40, Y=80, that is 40 bicycles should be produced. Tip : Constraint here should be Y=2X (i.e. Y-2X=0), since the number of wheels should be twice as much as number of frames (because every frame has to be equipped with two wheels – in case you never saw a bicycle 😊).