Proposta de Resolução
1.
1.1. 20
0= 1
1.2. (−20
)0= 1
1.3. −20
0= −1
1.4. −(−20
)0= −1
1.5. 5−2 = (1
5)
2
=1
25
1.6. (3
2)
−3
= (2
3)
3
=8
27
1.7. (− 4
10
)
−3
= (−10
4)
3
= −1000
64 = −125
8
2.
2.1. (−8
)−30 ÷(−2
)−30 = 4
−30 = (1
4)
30
2.2. (4
3)
−26
× (4
3)
16 =(4
3)
−10
= (3
4)
10
2.3. (8
7)−20×(−1
3)−20
(−1
5)−20 =(− 8
21)−20
(−1
5)−20 = (−8
21
−1
5
)
−20
= [− 8
21 × (−5
1)]
−20
= (40
21
)
−20
= (21
40
)
20
3.
3.1. 2−1×2−10
2−6 =2−11
2−6 = 2
−5
3.2. (10
4)3× 10
2× 5
−14 = 10
12 × 10
2× 5
−14 = 10
14 × 5
−14 = 10
14 × (1
5)
14
= (10
5)
14
= 2
14
3.3. 1625×16−5
(44)5=16
20
420 = 4
20 =(22)20 = 2
40
4. 𝑎−2 × 𝑎
4= 𝑎
2 OPÇÃO C
5. 1
125 = (1
5)
3
= 5
−3 OPÇÃO B
