Problem 1.36 [Difficulty: 1]
Given: Data on a container and added water.
Find: Weight and volume of water added.
Solution: Use Appendix A.
For the empty container Wc3.5 lbf⋅=
For the filled container Mtotal 2.5 slug⋅=
The weigh t of water is th en WwMtotal g⋅Wc
−=
Ww2.5 slug⋅32.2×ft
s2
⋅1 lbf⋅s2
⋅
1 slug⋅ft⋅
×3.5 lbf⋅−= Ww77.0 lbf=
The temperature is 90°F 32.2°C=and from Table A.7 ρ1.93 slug
ft3
⋅=
Hence Vw
Mw
ρ
=or Vw
Ww
gρ⋅
=
Vw77.0 lbf⋅1
32.2
×s2
ft
⋅1
1.93
×ft3
slug
⋅1 slug⋅ft⋅
1 lbf⋅s2
⋅
×= Vw1.24ft3
=