Quantitative Electrostatic Relationships - Microelectronics Technology | ECSE 2210, Study notes of Electrical and Electronics Engineering

Material Type: Notes; Professor: Schubert; Class: MICROELECTRONICS TECHNOLOGY; Subject: Electrical & Comp. Sys. Engr.; University: Rensselaer Polytechnic Institute; Term: Spring 2006;

Typology: Study notes

Pre 2010

Uploaded on 08/09/2009

koofers-user-lcu-1
koofers-user-lcu-1 🇺🇸

10 documents

1 / 5

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
1
1
Chapter 5-2 Quantitative electrostatic relationships
We make the analysis in 1 dimension, even though actual diode
as shown may not be a one-dimensional system. This makes the
analysis simple. The metallurgical junction is located at x= 0.
2
Quantitative analysis: Electric field E
pn
nD
pA
0s
;0
0
0
where
d
d
xxxx
xxN
q
xxN
q
K
x
<>=
<<
ε
=
<<
ε
=
ε=ε
ε
ρ
=
E
pn
NAND
xp0xn
W
Emax = q NA xp/ε
= qN
D xn/ε
np
nn
D
pp
A
;0
0)(
0)()(
xxxx
xxxx
qN
xxxx
qN
x
><=
ε
=
+
ε
=E
pf3
pf4
pf5

Partial preview of the text

Download Quantitative Electrostatic Relationships - Microelectronics Technology | ECSE 2210 and more Study notes Electrical and Electronics Engineering in PDF only on Docsity!

1

Chapter 5-2 Quantitative electrostatic relationships

We make the analysis in 1 dimension, even though actual diode as shown may not be a one-dimensional system. This makes the analysis simple. The metallurgical junction is located at x = 0.

2

Quantitative analysis: Electric field E

n p

D n

A p

s 0

where d

d

x x x x

N x x

q

N x x

q

K

x

ε

ε

ε= ε ε

ρ

E

p n

N A N D

x p 0 x n

W

E max = − q N A x p /ε = − q N D x n/ε

p n

n n

D

p p

A

x x x x

x x x x

qN

x x x x

qN x

ε

ε

E = −

3

Relationship between x n and x p

E max = − q N A x p / ε = − q N D x n / ε

N A x p = N D x n

Net charge on p-side = Net charge on n-side

Depletion layer width: W = x n + x p

A D

D p A

A n D N N

N

x W N N

N

x W

If N A >> N D, then Wx n and if N A << N D, then Wx p

4

Built-in voltage: V bi

V x x x

V x x

or ( )d d

d (^) n

p

E = − bi = − ∫ − E

V bi = − {area under E versus x curve}

= − (1/2) [ W (– q N D x n / ε) ]

= [ q / (2ε)] N D x n W

A D

A n A D

A D^2 since 2

N N

N

W x W N N

q N N

ε +

bi A D

2 A D

V

N N

N N

q

W

ε⎛ +

7

Effects of forward and reverse bias

8

PN-junction energy-band diagrams

9

Example 1

N D = 2 × 10 16 cm–3^ N A = 3 × 10 17 cm– N A = 1× 10 16 cm–3^ N D = 2 × 10 17 cm–

Consider the following diode. Calculate the maximum electric field, E max , the location of E max , the depletion layer width W , x n

and x p and the built-in voltage, V bi. Carefully plot the charge density, electric field, and the potential as a function of x.

Also, calculate the depletion layer width and the maximum electric field if a reverse voltage of 10 V is applied across the diode.

What will be W if V A = 0.5 V?

10

Example 2

Consider the diode of Example 1. Calculate the depletion layer

width and the maximum electric field if a reverse voltage of 10 V

is applied across the diode. Calculate the depletion layer width in

the n-side and p-side under this biased condition.

What will be W if V A = 0.5 V?

What happens if we apply V A > V bi?