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MATH 3339, Spring 2025, Final Review

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2024/2025

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Math 3339
Review for Final Exam - KEY
1. c. The interquartile range increases.
2. 0.003348589
3. --
4. b0 = y-intercept and b1= slope. Which of these will best explain the relationship
between x and y? b1
5. --
6. d . Deciding to go for the first down when his team will not get the first down.
7. 15/43
8. 9/20
9. a. [17.01, 26.79]
b. [29.75313, 170.9206]
10.
11. b. two-sample t-test for means
12. new mean = 5.64, new s=1.32
13. E[X] = 3.2, V[X] = 1.76
14. Median = 3.5 kg, shape is skewed right
15. b. A and C have reasonable intervals, but B does not.
16. [0.621, 0.779]
17. a. Fail to reject H0 at
b. Reject H0 at
c. two-sided t test vs. one-sided t test.
18. a. 1/4 b. 3/4
19. a. b. c. IT (higher R2 and lower
p-value)
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Math 3339

Review for Final Exam - KEY

  1. c. The interquartile range increases.
  2. --
  3. b0 = y-intercept and b 1 = slope. Which of these will best explain the relationship between x and y? b 1
  4. --
  5. d. Deciding to go for the first down when his team will not get the first down.
  6. 15/
  7. 9/
  8. a. [17.01, 26.79] b. [29.75313, 170.9206]
  9. b. two-sample t-test for means
  10. new mean = 5.64, new s=1.
  11. E[X] = 3.2, V[X] = 1.
  12. Median = 3.5 kg, shape is skewed right
  13. b. A and C have reasonable intervals, but B does not.
  14. [0.621, 0.779]
  15. a. Fail to reject H 0 at

b. Reject H 0 at

c. two-sided t test vs. one-sided t test.

  1. a. 1/4 b. 3/
  2. a. b. c. IT (higher R 2 and lower

p-value)

  1. a. np=2, too small b. since np and n(1-p) must each be at least 10, we will need 500 parts to sample c. Fail to reject H 0 at

  2. Fail to reject the null hypothesis. (this is a two sided proportions test, the test statistic is 0.3333 which does not fall in the rejection region for 1% significance)

  3. Reject H 0 at

  4. (two sample z test since we have population sd) test statistic is z=-7.28 => Reject the null and conclude there is a difference in the means.

  5. -0.

  6. 1537

  7. matched pairs t-test. Reject the null hypothesis

  8. a. success/fail, same prob for success, independent trials b. dbinom(4,6,.9)=0. c. pbinom(2,6,.9)=0. d. 1-pbinom(4,6,.9)=0.885735 (remember, this is discrete data)

  9. for , based on p-value given for data, reject the null at 5%

  10. 98

  1. a. r = .9255 r^2 =.

b. b = 1.158 t *^ = 1.860 SE (^) b =.

This means that I am 90% confident the true slope of the LSRL of math and verbal scores on the SAT will lie in this interval. OR: I am 90% confident that for every 1 point increase in math SAT score, the average increase in verbal SAT score will be between .846 and 1.467. c.

Conclusion: Based on 5% significance level, I will reject the null hypothesis which states that there is no linear relationship between math and verbal scores on the SAT.

  1. a.

b. On average, for each 1 point increase in the problem solving sub score, the was an increase of 4.0162 points in the total score. c. R 2 indicates that 62% of the variation in total scores can be explained by the LSRL of total scores on problem solving sub score. d.

e. All assumptions check.

Based on 5% significance level I will reject the null hypothesis which states that there is no linear relationship between problem solving sub scores and total scores on the exam.