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PROBLEM 10.22. known: Ri34a is the working fluid in a vapor - compression refrigeraton Squtema having a water cooled Condençer. Ths apa w Enown and Alho comprstion process «à doseribed h pulo!= conctant. ErmD: Determune (a) ths mais flow rate q RiS4a, (b) power rnputo and hat trancfay Asts for tha Comprsstor, €0) coeftrcient % perfovmasu , (d) coslimo tonta mass flu rate, ce) rater exoraa dosiructim tu tino conde nta and dog para em valve, A erpused as a percentage b ta poseo input. cooling water ao! 30º€. Pe tio bar meme CHEMATIC & GIVEN Condenser T = ==4 ! | ! Pa=(2 bar A. cla É é Expansit 1 E AR Prim [e a I p-s===. de [> (RES 1 “4 bar 1 I =. LA | TEM 2 Qn = IO tons ENGINEERING . MODEL: (1) Each componeut is analyzed as à control volume at steady sinte..(21 The Compressiem ie polybmepio mid n=(.01, (3) The expansion Hucougln Mmevolve is a Hurotl Lun poe 0x) Heat trausfer from (he outside of He condenser cam be negle ted. (5) kenetic amd potenhiod eneray effects ave negligible, (o) bet To = 243. ANBNSIS: First; fix cock of the principal states. State L prubar,T=IS% => h,=258.15 7] 3 3,=9248 Mg As =0.05258 mYks State 7. For tue polytropic process, P; = 12 bar and = (Ejs = 001172 M3/%g From Table kz 3 ho =2231.33 kT/kg ; 342 434] T/ka-k State 3 T;=U4*C, compressed Liquid => h= WylM42C) =112.722 KT/kg S4% SplU40C) = 04054 k3/kak Sale % Throttliug process > hy =hs = 112.22 7/k9 Equation 6.55 is used to determime fha compressor work. inpudo É E mp P " E mn We = Lorde = (equi) - (1.01 3 o Ulyz VkT < (E ) [tia har Ico RA) -(u)(052 s8) 1) Ce Ie | 23.432k]/4. The mass Flow rate is dona using te vefrigerating capacity nã Qu 10 tons) TU ESfraia [mi hoy Gssas ias | Lion fis =0.24) kg/s 4a