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PROBLEM 10.33 now»: Am ideal vaper-compression refrigeratim we is modified to ncluda À counterhow heat Ernani Pbbgpena, tre strenms onA ou e. exitina the condenser Amecnra 14 tne ortrvag Cluid. Data are known at various locations, cu mass flow rate is quem. EIND: Dotermineça) Ye vefrigeratina capacity, (b) the compressor power pi te) He c eRbicicus dé performance. , CHEMATY VBA) 2 4 Rout z e o cl -=—— T , la of 1 Condenser o $ Liber 1, o, “oe Emas jade, Te 1 É / t S% 1 tobar s %€. 1 í Heat exchanger ENSVEERING MODEL; Same as Exam ple 10,1 > items 1-4, Also ascume no heat loss From the outside of Lhe heat excuonger, 4 ANALYSIS First, Eix each ot Me prine pal ! states, 18 bas via =iZ leginia Expansion à valve == = — —=s ==, Exeporator | 1 State b p,=l,S bar pSat.vupom Co bar => hç= Bagyi K3/bg S a Sat.vapor Ste L patobar,T=S% Ah MBLIS Laio , all Eita atuo 2 p=lgbar ,S.=5, =D h,= 2028,54 ky/kg Snes pralgbar ,T;=40"€ => emmp.liquid ; hz heC40ºC) = 371.35 kTIkg Stode ig, Ustng aw energy balauce ow tuo heok exchange control voluia o. vn (bh) prin l hos) or hg= ho-horhas =286.S1 KT/ leg Slate 5 Threttlvag process = hs ahy = 286.51 LT/kg (al The refrigerarwg capacity ls ag = (hç-hs) (no (Remi — 28465) E) Cb) Te, compressor power is . Ee x Wez will) (0108 ) penia p zors sy gas) a 0 |- 108,5 Wee (Cy Tha coefiticat of perforwanca vs gr bihs/Cho-hy) 2209 + & — tem 1. [EA ur s/a) = ON Mons q O Discussion: The heat enchanger (1) temas to increase Hhe acity, (2) helps ensure Superheated vapor enterino the Compressor ave (3) increuses He ANerage specific volume in He compressor, tereby mereasing He poser required.