Microelectronics Technology - Detailed Quantitative Analysis | ECSE 2210, Study notes of Electrical and Electronics Engineering

Material Type: Notes; Class: MICROELECTRONICS TECHNOLOGY; Subject: Electrical & Comp. Sys. Engr.; University: Rensselaer Polytechnic Institute; Term: Fall 2006;

Typology: Study notes

Pre 2010

Uploaded on 08/09/2009

koofers-user-bvi
koofers-user-bvi 🇺🇸

10 documents

1 / 8

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
1
1
Chapter 11-1 Detailed Quantitative Analysis
pnp transistor, steady state, low-level injection.
Only drift and diffusion, no external generations
One dimensional etc.
Assumptions:
General approach is to solve minority carrier
diffusion equations for each of the three regions:
The goal is to relate transistor performance parameters
(
γ
,
α
T,
β
dc etc. ) to doping, lifetimes, base-widths etc.
L
G
p
x
p
D
t
p+
τ
=
p
2
2
pL
n
2
2
nG
n
x
n
D
t
n+
τ
=
and
2
General Quantitative Analysis
Under steady state and when GL= 0,
0
n
2
2
n=
τ
n
x
n
D
0
p
2
2
p=
τ
p
x
p
Dand
For the base in pnp, we are interested only in holes.
0
p
2
2
p=
τ
p
x
p
D
The rigorous analysis is carried out in chapter 11, but we are going to take
a more simplified approach.
pf3
pf4
pf5
pf8

Partial preview of the text

Download Microelectronics Technology - Detailed Quantitative Analysis | ECSE 2210 and more Study notes Electrical and Electronics Engineering in PDF only on Docsity!

1

Chapter 11-1 Detailed Quantitative Analysis

pnp transistor, steady state, low-level injection. Only drift and diffusion, no external generations One dimensional etc.

Assumptions:

General approach is to solve minority carrier

diffusion equations for each of the three regions:

The goal is to relate transistor performance parameters

( γ, αT , βdc etc. ) to doping, lifetimes, base-widths etc.

G L

p x

p D t

p

τ

(^2) p

2 p L (^2) n

2 n G

n x

n D t

n

τ

and ∂∆

2

General Quantitative Analysis

Under steady state and when G L= 0,

(^2) n

2 n (^) τ =

∂ ∆ n x

n 0 D (^2) p

2 p (^) τ =

∂ ∆ p x

p D and

For the base in pnp, we are interested only in holes.

p 2

2 p = τ

∂ ∆ p x

p D

The rigorous analysis is carried out in chapter 11, but we are going to take a more simplified approach.

3

Review: Operational Parameters

These parameters can be related to device parameters such as doping, lifetimes, diffusion lengths, etc.

Base transport factor : αT = I C / I EP

Collector to emitter current gain: αDC = αT γ

Collector to base current gain: βDC = αDC / (1 – αDC )

Injection Efficiency : γ= I EP /( I EP+ I EN)

I E I C

I B

I EP

  • I EN

I BR

  • I BE – I BR

4

Review: Indirect thermal recombination-generation

n 0 , p 0 – under thermal equilibrium n , p – under arbitrary conditions, functions of t

n = nn 0 ∆ p = pp 0

Low-level injection condition is assumed.

  • Change in the majority carrier concentration is negligible. For example, in n-type material, ∆ p << n 0 ; nn 0. in p-type material, ∆ n << p 0 ; pp 0.

n and ∆ p are deviations in carrier concentrations from their equilibrium values. ∆ n and ∆ p can be both positive or negative. ∆ n and ∆ p are termed excess carriers – excess above the equilibrium concentration.

Majority carriers are electrons in n-type material and holes in p-type material.

7

Review of P-N Junction Under Forward Bias (cont.)

I n = q A D E d∆ n /d x E = – ( q A D E/ L E ) ∆ n E(0) I p = – q A D B d∆ p /d x B = ( q A D B/ L B) ∆ p B(0)

Total current I = I P + (– I N) (“–” because x E and x B point in opposite directions)

= ( q A D B/ L B) ∆ p B(0) + ( q A D E/ L E) ∆ n (^) E (0)

= ( q A D B/ L B) p B0 [ exp ( q V EB / kT ) – 1 ] +

  • ( q A D E/ L E) n E0 [ exp ( q V EB / kT ) – 1 ]

≈ ( q A D B/ L B) p B0 exp ( q V EB/ kT ) + ( q A D E/ L E) n E0 exp ( q V EB/ kT )

Note : I p and I n can also be calculated based on the fact that Q p has to be replaced every τ B seconds Î I p = Q p / τ B and I n = Q n / τ E and I E = I P + I N

8

Simplified Analysis

Consider the carrier distribution in a forward active pnp transistor

n E0^ p B

n C

Emitter Base Collector

n C(0)

p B(0)

n E(0)

9

Simplified Analysis (cont.)

n E0 , p B0 and n C0 = equilibrium concentration of minority carriers in emitter, base and collector

n E(0), p B(0) and n C(0) = minority carrier concentration under forward active conditions at the edge of the respective depletion layers

n E (0), ∆ p B(0) and ∆ n C(0) = excess carrier concentration at the edge of the depletion layers

E

(p+)

B

(n)

C

(p)

10

Simplified Analysis (cont.)

n E (0) = n E (0) – n E0 = n E0 [exp ( q V EB / kT ) – 1]

p B (0) = p B (0) – p B0 = p B0 [exp (q V EB / kT ) – 1]

By taking the slopes of these minority carrier distribution at the depletion layer edges and multiplying it by “ q A D n,p ”, we can get hole and electron currents.

Note that I n = q A D n (d n / d x ) and I p = – q A D p (d p / d x )

13

Calculation of Currents (cont.)

Emitter Current (cont.)

I EN corresponds to electron current injection from base to emitter since E-B junction is forward biased.

I EN = q A ( D (^) E / L E) n E0 [exp ( q V EB / kT ) – 1 ] ≈ q A ( D (^) E / L E) n E0 [exp ( q V EB / kT )] ---- (C)

14

Calculation of Currents (cont.)

Base Current, I B

-supplies electrons for recombination in base -supplies electrons for injection to emitter

I B =^ q A p B0 [ W B / (2^ τB )] [exp ( qV EB /^ kT ) ]

q A ( D (^) E / L E) n E0 exp ( qV EB / kT )

( recombination) + (electron injection to emitter)

Now we can find transistor parameter easily.

15

Calculation of Currents (cont.)

Base transport factor , α (^) T

(same as eq. 11.42 in text)

B B 0 B

E E 0 E /

/ 1

1

D p W

D n L

=

2

B

B 0 EB B B

EB B B 0 B

B

EB B 0 B

B

EP

T C

2

1 1

1 exp 2

exp

exp

⎟⎟ ⎠

⎞ ⎜⎜ ⎝

=

τ ⎟+ ⎠

⎞ ⎜ ⎝

⎟ ⎠

⎞ ⎜ ⎝

α = =

L

W kT

qV p qAW kT

qV p W

qAD

kT

p qV W

qAD

I

I

Emitter injection efficiency, γ

γ = I EP / [ I EP + I EN ]

= 1 / [ 1 + I EN / I EP ]

= 1 / [ 1 + (C) / (B) ]

16

Calculation of Currents (cont.)

Î n E0 = n i^2 / N E … doping in emitter Î p B0 = n i^2 / N B … doping in base

B E E

E B B B E B

E B E 01

D L N

D W N

D L p

D W n

γ = (Eq 11.41 in textbook)

αdc = γ αT

βDC = αDC / (1– αDC )