Straight Slender - Mechanics - Lab, Study notes of Applied Mechanics

The main points in the lab notes of mechanics are: Straight Slender, Intermediate, Compressive Load, Column Behavior, Critical Stress, Values, Experimentally, Subjected, Relatively Short, Material

Typology: Study notes

2012/2013

Uploaded on 05/08/2013

anandini
anandini 🇮🇳

4.7

(9)

119 documents

1 / 10

Toggle sidebar

This page cannot be seen from the preview

Don't miss anything!

bg1
2/11 04/07/01
I. OBJECTIVES
1.1 To determine the effect the slenderness ratio has on the load
carrying capacity of pin ended columns.
1.2 To observe short, intermediate and long column behavior under the
application of a compressive load.
1.3 To compare experimentally observed values of critical stress with
the theoretical values.
II. BACKGROUND
A straight slender member subjected to an axial compressive load is called
a column. If such a member is relatively short, it will remain straight when
loaded, and failure will occur by yielding of the material (in the case of
wood crushing of the fibers will occur). However, if the member is relatively
long a different type of behavior will be observed. When the compressive
load reaches a so called “critical load” a long column will undergo a
bending action in which the lateral deflection will become very large with
little increase in load. This behavior is called “buckling” and can occur
even though the maximum stress in the column is less than the yield
stress of the material. The load at which a column will buckle is affected by
material properties, column length and cross section, and end conditions.
If a long slender bar of constant cross
section is pinned at each end, the applied
compressive load, Pcr that will cause
buckling is:
2
2
)KL(
EI
Pcr π
ππ
π
=
==
=5.1
Where:
E = Modulus of elasticity.
I = Minimum moment of inertia of cross-sectional area about an
axis through the centroid.
L = Length of the bar.
K = Effective length constant (KL = effective length)
P
Lateral deflection of
column produced by
buckling
Docsity.com
pf3
pf4
pf5
pf8
pf9
pfa

Partial preview of the text

Download Straight Slender - Mechanics - Lab and more Study notes Applied Mechanics in PDF only on Docsity!

2/11 04/07/

I. OBJECTIVES

1.1 To determine the effect the slenderness ratio has on the load carrying capacity of pin ended columns.

1.2 To observe short, intermediate and long column behavior under the application of a compressive load.

1.3 To compare experimentally observed values of critical stress with the theoretical values.

II. BACKGROUND

A straight slender member subjected to an axial compressive load is called a column. If such a member is relatively short, it will remain straight when loaded, and failure will occur by yielding of the material (in the case of wood crushing of the fibers will occur). However, if the member is relatively long a different type of behavior will be observed. When the compressive load reaches a so called “critical load” a long column will undergo a bending action in which the lateral deflection will become very large with little increase in load. This behavior is called “buckling” and can occur even though the maximum stress in the column is less than the yield stress of the material. The load at which a column will buckle is affected by material properties, column length and cross section, and end conditions.

If a long slender bar of constant cross section is pinned at each end, the applied compressive load, P (^) cr that will cause buckling is:

2

2

(KL)

EI

Pcr

Where:

E = Modulus of elasticity. I = Minimum moment of inertia of cross-sectional area about an axis through the centroid. L = Length of the bar. K = Effective length constant (KL = effective length)

P

Lateral deflection of column produced by buckling

3/11 04/07/

This formula was first obtained by the Swiss mathematician, Leonard Euler (1707-1783) and the load P (^) cr is called the Euler buckling load (see Appendix A for the derivation).

Euler’s formula defines a boundary above which elastic instability occurs in a compression member. To make it independent of the size of the member it is frequently written in terms of stress rather than load.

2

2 2

2 cr

r

KL

E

(KL) A

EI

A

Pcr

 

ππππ

ππππ σσσσ ==== ==== 5.

where L/r is called the slenderness ratio and r is the radius of gyration. The radius of gyration can be computed from the equation:

A

I

r ==== 5.

The effective length Le = KL depends on the support boundary conditions which are summarized in the table below:

5/11 04/07/

The two material properties of interest in this experiment are the crushing strength and modulus of elasticity in bending for Douglas Fir. Mark’s handbook implies, based on data from the U.S. Forest Products Laboratory, that both of these material properties are directly related to the specific gravity of the wood. Average values at 12% moisture content, for Douglas Fir are:

specific gravity (SG) = 0. modulus of elasticity in bending (E) = 1,950,000 psi

maximum crushing strength ( σσσσ ys) = 7430 psi

Since the modulus and the crushing strength vary directly with the specific gravity, the critical stress values obtained from the experiment may be adjusted using the values you determine for the specific gravity:

exp

SGexp

6/11 04/07/

III. EQUIPMENT

3.1 Instron test machine.

3.2 Assorted small tools.

MATERIALS

Six specimens of nominal 0.7 in x 0.7 in. Douglas Fir of varying lengths.

These specimens used in this experiment are selected at random from the wood shop. No attempt has been made to cut each length member from the same piece of wood. Thus the results may be expected to vary considerably; however, by adjusting the data for specific gravity an attempt will be made to reduce the scatter and explain the results.

The weight of each member, in ounces, will be needed to calculate the specific gravity of each piece. First, the weight per cubic inch of each member is obtained by dividing its weight by its actual volume in cubic inches (cu. in.) then, dividing by standard weight of water, 0.5778 oz/in^3 , the specific gravity of each member is obtained.

IV. PROCEDURE

4.0 Measure and weigh the wood samples.

4.1 Calculate the theoretical Euler buckling load and stress. Calculate the theoretical maximum crushing load (the maximum crushing stress is given).

4.2 Turn the computer on.

4.3 Pull out the emergency stop button (red button) on the right hand side of the Instron machine. Two green arrows will light.

4.4 Check that the upper and lower bearing plates are aligned vertically then place the longest column in the bearing plates.

4.5 Place the wire cage around the machine.

8/11 04/07/

  1. Select run to test the new column and repeat the above steps until all the columns are tested.

D. To exit, use the ESC key to get to the main menu then Exit (X). Turn off the computer. Push in the red knob to turn off the instron machine.

V. REPORT

5.1 Plot the following curves on the same graph using (^) σσσσ =Pcr/A as ordinate and L/d as abscissa:

a. Two experimental curves, using P (^) cr/A and L/d as obtained and measured in the laboratory. Plot the “raw” data and the adjusted data.

b. The theoretical curve plotted from the Euler column formula (Equation 5.4). If using Excel, double click on the y axis and set the maximum scale value to 14,000 (psi). This is required because the Euler buckling stress will approach infinity as the length approaches zero.

c. The horizontal line indicating the maximum crushing stress.

5.2 Indicate directly on the figure (as in the figure in the text) the range of values of L/d corresponding to short columns, intermediate columns, and long columns.

5.3 Discuss the results and draw appropriate conclusions.

SELECTED REFERENCES

6.1 Statics and Strength of Materials. Stevens, Ch. 10.

6.2 Mark’s Standard Handbook for Mechanical Engineers. 8th^ Edition. McGraw Hill, Chapter 6, pp. 123, 125.

6.3 An Introduction to the Mechanics of Solids. Crandel and Dahl.

9/11 04/07/

DATA SHEET EXPERIMENT # 5

BUCKLING

Student Name ___________________ Group #____________________

Date Exp. Performed ______________Instructor’s Name____________

Specimen Number 1 2 3 4 5 6 Specimen Length (Inches) Effective Length KL (Inches) Least Cross Section Dimension dmin (Inches) Greatest Cross Section Dimension dmax (Inches) Cross. Section Area (sq. in) Slenderness Ratio (L/dmin) Weight (Oz.) Specific Gravity = Density/0. Max. Crushing

Strength σσσσys (psi)

Max. Compressive Expected Load (lb) Calculated Euler Pcr (lb) Pcr/A Euler Calculated (psi) Failure Load (Pcr) Experimental (lb) Experimental Failure Stress Pcr/A (psi) Adjusted Experimental Stress Pcr/A (psi)

11/11 04/07/

We next apply boundary conditions: at x = 0, y = 0 and at x = L, y = 0. That is, the deflection of the column must be zero at each end since it is pinned. Applying the first boundary condition, it is noted that B must be zero since cos(0) = 1. The second boundary condition implies that either A must be zero (which leaves us with no equation at all) or that:

Noting that sin(ππππ) = 0, we can solve for P:

where Pcr stands for the critical load at which the column is predict ed to buckle.

By replacing L with the effective length, KL, we can generalize the formula to predict the critical load for Fixed-Pinned, Fixed-Fixed, and Fixed-Free columns.

It should be noted that buckling is a complicated phenomena, and the buckling in any individual column may be influenced by misalignment in loading, variations in straightness of the member, presence of initial unknown stresses in the column, and defects in the material.