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1 4
ln √ x
√ x
3
= (^1) f ( x )=
ln √ x
√ x
∫ a b f ( x ) dx = b − a 8
∫ 1 4
ln √ x
√ x
3
[ f^ (^1 )+^3 f^ (^2 )+^3 f^ (^3 )^ + f^ (^4 )]
∫ 1 4
ln √ x
√ x
3
8 [^
ln √ 1
√^1
3
ln √ 2
√^2
3
ln √ 3
√^3
3
ln √ 4
√^4
3
1 4
ln √ x
√ x
3
1
x 3
. lnx (^) dx h = b − a 3
=0.4 (^) f(x) = (^) x^3_. lnx_ ∫ a b f ( x ) dx = b − a 8
∫ 1
x 3
. lnx dx =^
[ f ( 1 ) + 3 f (1.4 ) + 3 f ( 1.8) + f (2.2)]
∫ 1
x 3
. lnx dx =
[ 1 3
. ln 1 + 3 (1. 3 . ln (1.4))+ 3 (1. 3 . ln (1.8))+2. 3 . ln (2.2)] ∫ 1
x 3 . lnx dx = 3.21739 (^) u^2
0 3 e x
. senx 1 + x 2 dx h = b − a 3
= (^1) f(x) = e x
. senx 1 + x 2
a b f ( x ) dx = b − a 8
0 3 e x
. senx 1 + x 2 dx =^
[ f^ (^0 )^ +^3 f^ (^1 )^ +^3 f^ (^2 )^ + f^ (^3 )]
0 3 e x
. senx 1 + x 2 dx =^
8 [^
e 0
. sen ( 0 ) 1 + 02
e 1
. sen ( 1 ) 1 + 12
e 2
. sen ( 2 ) 1 + 22
e 3
. sen ( 3 )
1 + 32 ]
0 3 e x
. senx 1 + x 2 dx =^ 2.90467^ u 2
2 4 ln 3 x dx h =
3 ∫ a
b f ( x ) dx = b − a 8 [ f^ (^ xo )+^3 f^ (^ x 1 )+ f^ ( x 2 )+ f^ (^ x 3 )]
2 4 ln 3 x dx =¿
8 [
f ( 2 )+ 3 f (
)+ f (
)+ f ( 4 )
]
2 4 ln 3 x dx =¿
4 [^
ln^3 ( 2 )+ 3
[
ln^3 (
)+ln^3 (
]
]
2 4 ln 3 x dx =¿
[ 0.33302+ 3 [ 0.94358+ 1.74522]+2.66420 ]
2 4 ln 3 x dx =¿ (^) 2.76591 u^2
− 3 3
ln( x
2
+ 4 ) dx
h =
a b f ( x ) dx = b − a 8 [ f^ (^ xo )+^3 f^ ( x 1 )+ f^ (^ x 2 )+ f^ (^ x 3 )]
− 3 3
ln (^ x
2
+ 4 )^ dx =
[ f^ (−^3 )+^3 f^ (−^1 )+ f^ (^1 )+^ f^ (^3 )]
− 3 3
ln (^ x
2
+ 4 )^ dx =
[ ln^ ((−^3 )
2
+ 4 )+ 3 [ ln((− 1 )
2
+ 4 )¿+ln (( 1 )
2
+ 4 ) ] +ln (( 3 )
2
+ 4 ) ]
