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EPSEB - EGT ALGEBRA PRACTICE 5 21 / 12 / 10
In this practice we will learn how to plot a curve given by an implicit equation and will
apply what we learned in previus practices about coordinate transformations
restart:with(LinearAlgebra):with(plots):
In the Maple Help, look for how to plot an implicit curve with the sentence "implicitplot".
Then, plot the conical curve
K
2 x
2
C52 x
K
198
K
12 x yC60 y
K
2 y
2
= 0
curve:=-2*x^2+52*x-198-12*x*y+60*y-2*y^2 = 0;
implicitplot(curve,x=-10..10, y=-10..10,scaling=constrained);
curve :=
K
2 x
2
C52 x
K
198
K
12 x yC60 y
K
2 y
2
= 0
x
K
10
K
505 10
y
K
10
K
5
5
10
Now apply an axis translation to the point (4,3) and a 30º axis rotation to the conical.
Find the equation and plot the conical in the new axis
Let's do it in 2 steps.
First let's translate the origin to the point (4,3)
curve2:=subs(x=X+4,y=Y+3,curve);
implicitplot(curve2,X=-10..10, Y=-10..10,scaling=constrained)
;
