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Trigonometria, Apuntes de Análisis Matemático

Asignatura: Analisi I, Profesor: , Carrera: Matemàtiques, Universidad: UV

Tipo: Apuntes

2014/2015

Subido el 16/07/2015

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Lecture Notes Trigonometric Identities 1 page 1
Sample Problems
Prove each of the following identities.
1. tan xsin x+ cos x= sec x
2. 1
tan x+ tan x=1
sin xcos x
3. sin xsin xcos2x= sin3x
4. cos
1 + sin +1 + sin
cos = 2 sec
5. cos x
1sin xcos x
1 + sin x= 2 tan x
6. cos2x=csc xcos x
tan x+ cot x
7. sin4xcos4x
sin2xcos2x= 1
8. tan2x
tan2x+ 1 = sin2x
9. 1sin x
cos x=cos x
1 + sin x
10. 12 cos2x=tan2x1
tan2x+ 1
11. tan2= csc2tan21
12. sec x+ tan x=cos x
1sin x
13. csc
sin cot
tan = 1
14. sin4xcos4x= 1 2 cos2x
15. (sin xcos x)2+ (sin x+ cos x)2= 2
16. sin2x+ 4 sin x+ 3
cos2x=3 + sin x
1sin x
17. cos x
1sin xtan x= sec x
18. tan2x+ 1 + tan xsec x=1 + sinx
cos2x
c
copyright Hidegkuti, Powell, 2009 Last revised: May 8, 2013
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Sample Problems

Prove each of the following identities.

  1. tan x sin x + cos x = sec x

tan x

  • tan x =

sin x cos x

  1. sin x sin x cos^2 x = sin^3 x

cos 1 + sin

1 + sin cos = 2 sec

cos x 1 sin x

cos x 1 + sin x

= 2 tan x

  1. cos^2 x = csc x cos x tan x + cot x

sin^4 x cos^4 x sin^2 x cos^2 x

tan^2 x tan^2 x + 1 = sin^2 x

1 sin x cos x

cos x 1 + sin x

  1. 1 2 cos^2 x = tan^2 x 1 tan^2 x + 1
  2. tan^2  = csc^2  tan^2  1
  3. sec x + tan x = cos x 1 sin x

csc sin

cot tan

  1. sin^4 x cos^4 x = 1 2 cos^2 x
  2. (sin x cos x)^2 + (sin x + cos x)^2 = 2

sin^2 x + 4 sin x + 3 cos^2 x

3 + sin x 1 sin x

cos x 1 sin x tan x = sec x

  1. tan^2 x + 1 + tan x sec x = 1 + sin x cos^2 x

Practice Problems

Prove each of the following identities.

  1. tan x + cos x 1 + sin x

cos x

  1. tan^2 x + 1 = sec^2 x

1 sin x

1 + sin x = 2 tan x sec x

  1. tan x + cot x = sec x csc x

1 + tan^2 x 1 tan^2 x

cos^2 x sin^2 x

  1. tan^2 x sin^2 x = tan^2 x sin^2 x

1 cos x sin x

sin x 1 cos x = 2 csc x

sec x 1 sec x + 1

1 cos x 1 + cos x

  1. 1 + cot^2 x = csc^2 x

csc^2 x 1 csc^2 x = cos^2 x

cot x 1 cot x + 1

1 tan x 1 + tan x

  1. (sin x + cos x) (tan x + cot x) = sec x + csc x

sin^3 x + cos^3 x sin x + cos x = 1 sin x cos x

cos x + 1 sin^3 x

csc x 1 cos x

1 + sin x 1 sin x

1 sin x 1 + sin x = 4 tan x sec x

  1. csc^4 x cot^4 x = csc^2 x + cot^2 x

sin^2 x cos^2 x + 3 cos x + 2

1 cos x 2 + cos x

tan x + tan y cot x + cot y = tan x tan y

1 + tan x 1 tan x

cos x + sin x cos x sin x

  1. (sin x tan x) (cos x cot x) = (sin x 1) (cos x 1)
  1. cos^2 x =

csc x cos x tan x + cot x Solution: We will start with the right-hand side. We will re-write everything in terms of sin x and cos x and simplify. We will again run into the Pythagorean identity, sin^2 x + cos^2 x = 1.

RHS =

csc x cos x tan x + cot x

sin x

 cos x sin x cos x

cos x sin x

sin x

cos x 1 sin^2 x sin x cos x

cos^2 x sin x cos x

cos x sin x sin^2 x + cos^2 x sin x cos x

cos x sin x 1 sin x cos x = cos x sin x

cos x sin x 1

cos^2 x 1 = cos^2 x = LHS

sin^4 x cos^4 x sin^2 x cos^2 x

Solution: We can factor the numerator via the di§erence of squares theorem.

LHS =

sin^4 x cos^4 x sin^2 x cos^2 x

sin^2 x

(cos^2 x)^2 sin^2 x cos^2 x

sin^2 x + cos^2 x

sin^2 x cos^2 x

sin^2 x cos^2 x = sin^2 x + cos^2 x = 1 = RHS

tan^2 x tan^2 x + 1 = sin^2 x

Solution:

LHS =

tan^2 x tan^2 x + 1

sin x cos x

sin x cos x

sin^2 x cos^2 x sin^2 x cos^2 x

sin^2 x cos^2 x sin^2 x cos^2 x

cos^2 x cos^2 x

sin^2 x cos^2 x sin^2 x + cos^2 x cos^2 x

sin^2 x cos^2 x 1 cos^2 x

sin^2 x cos^2 x

cos^2 x 1 = sin^2 x = RHS

1 sin x cos x

cos x 1 + sin x Solution:

LHS = 1 sin x cos x

1 sin x cos x

1 sin x cos x

1 + sin x 1 + sin x

(1 sin x) (1 + sin x) cos x (1 + sin x)

1 sin^2 x cos x (1 + sin x)

= cos^2 x cos x (1 + sin x)

cos x 1 + sin x

= RHS

  1. 1 2 cos^2 x = tan^2 x 1 tan^2 x + 1 Solution:

RHS =

tan^2 x 1 tan^2 x + 1

sin^2 x cos^2 x

sin^2 x cos^2 x

sin^2 x cos^2 x

cos^2 x cos^2 x sin^2 x cos^2 x

cos^2 x cos^2 x

sin^2 x cos^2 x cos^2 x sin^2 x + cos^2 x cos^2 x = sin^2 x cos^2 x cos^2 x

cos^2 x sin^2 x + cos^2 x

sin^2 x cos^2 x sin^2 x + cos^2 x

sin^2 x cos^2 x 1 = sin^2 x cos^2 x =

1 cos^2 x

cos^2 x = 1 2 cos^2 x = LHS

  1. tan^2  = csc^2  tan^2  1

RHS = csc^2  tan^2  1 =

sin^2 

sin  cos 

sin^2 

sin^2  cos^2 

cos^2 

cos^2 

cos^2  cos^2 

1 cos^2  cos^2 

sin^2  cos^2 

sin  cos 

= tan^2  = LHS

  1. sec x + tan x = cos x 1 sin x Solution:

RHS = cos x 1 sin x

cos x 1 sin x

cos x 1 sin x

1 + sin x 1 + sin x

cos x (1 + sin x) (1 sin x) (1 + sin x) = cos x (1 + sin x) 1 sin^2 x

cos x (1 + sin x) cos^2 x

1 + sin x cos x

cos x

sin x cos x

= LHS

csc sin

cot tan

Solution: We will start with the left-hand side. We will re-write everything in terms of sin and cos and simplify. We will again run into the Pythagorean identity, sin^2 x + cos^2 x = 1 for all angles x.

LHS =

csc sin

cot tan

sin sin 1

cos sin sin cos

sin

sin

cos sin

cos sin

sin^2

cos^2 sin^2

1 cos^2 sin^2

sin^2 + cos^2

cos^2 sin^2

sin^2 sin^2

= 1 = RHS

  1. sin^4 x cos^4 x = 1 2 cos^2 x

Solution: LHS = sin^4 x cos^4 x =

sin^2 x

cos^2 x

sin^2 x + cos^2 x

sin^2 x cos^2 x

sin^2 x cos^2 x

1 cos^2 x

cos^2 x = 1 2 cos^2 x = RHS