

























Estude fácil! Tem muito documento disponível na Docsity
Ganhe pontos ajudando outros esrudantes ou compre um plano Premium
Prepare-se para as provas
Estude fácil! Tem muito documento disponível na Docsity
Prepare-se para as provas com trabalhos de outros alunos como você, aqui na Docsity
Encontra documentos específicos para os exames da tua universidade
Prepare-se com as videoaulas e exercícios resolvidos criados a partir da grade da sua Universidade
Responda perguntas de provas passadas e avalie sua preparação.
Ganhe pontos para baixar
Ganhe pontos ajudando outros esrudantes ou compre um plano Premium
Este documento aborda a transformada de laplace, sua definição, propriedades e exemplos. A transformada de laplace é uma ferramenta matemática utilizada para analisar sinais e sistemas, permitindo a transformação de sinais no domínio do tempo para o domínio da frequência. O documento abrange conceitos básicos, como a linearidade, a transformada inversa, escalonamento temporal e espacial, escalonamento exponencial e aplicação a circuitos elétricos e sistemas de controle.
Tipologia: Notas de aula
1 / 33
Esta página não é visível na pré-visualização
Não perca as partes importantes!


























S. Boyd
EE
definition & examples
-^
properties & formulas –^
linearity
-^
the inverse Laplace transform
-^
time scaling
-^
exponential scaling
-^
time delay
-^
derivative
-^
integral
-^
multiplication by
t
convolution
the Laplace transform converts
integral
and
differential
equations into
algebraic
equations
this is like phasors, but^ •
applies to general signals, not just sinusoids • handles non-steady-state conditions allows us to analyze^ •
LCCODEs • complicated circuits with sources, Ls, Rs, and Cs • complicated systems with integrators, differentiators, gains The Laplace transform
we’ll be interested in signals defined for
t
the
Laplace transform
of a signal (function)
f
is the function
(f
defined by
(s
∞ 0
f^ (
t)
−e
st
dt
for those
s
for which the integral makes sense
is a complex-valued function of complex numbers
-^
s^
is called the (complex)
frequency variable
, with units sec
−
t
is called
the
time variable
(in sec);
st
is unitless
for now, we assume
f
contains no impulses at
t
common notation convention:
lower case letter denotes signal; capital
letter denotes its Laplace transform,
e.g.
denotes
(u
in
denotes
(v
in
), etc.
The Laplace transform
let’s find Laplace transform of
f
(t
e
t:
(s
∞ 0
t e e
−
st
dt
∞ 0
(1 e
−
s)
t^ dt
s
(1e
−
s)
t
s^
provided we can say
e
(
−
s)
t^ →
as
t
, which is true for
s >
∣ ∣e∣
(
−
s)
∣ ∣t∣
∣ ∣e∣
−
j(
=s
)t
=
∣ ∣e∣
(
−<
s)
∣ ∣t∣
e
(
−<
s)
t
the
integral
defining
makes sense for all
s
with
s >
(the
‘region of convergence’
of
but the resulting
formula
for
makes sense for all
s
except
s
we’ll ignore these (sometimes important) details and just say that
(e
t) =
s^
The Laplace transform
sinusoid:
first express
f
(t
) = cos
ωt
as
f^
(t
jωte
−e jωt
now we can find
as
(s
∞ 0
− e
st
jωte
−e
jωt
dt
∞ 0
( e −
s+
jω
)t
dt
∞ 0
( e −
s−
jω
)t
dt
s^
jω
s^
jω
s (^2) s
ω
2
(valid for
s >
; final formula OK for
s
jω
The Laplace transform
powers of
t
f^ (
t) =
t
n^
(n
we’ll integrate by parts,
i.e.
, use
b^ u a
(t
)v
t)
dt
u
(t
)v
(t
b a
b^ v a
(t
)u
t)
dt
with
u
(t
t
n,
v
t) =
e
−
st
a^
b^
(s
∞ 0
n t
−e
st
dt
nt
−e
st s
n s
∞ 0
n t −
1 e
−
st
dt
n^ s^
(t
n−
provided
t
ne
−
st
if
t
, which is true for
s >
applying the formula recusively, we obtain
(s
n! n+1 s
valid for
s >
; final formula OK for all
s
The Laplace transform
the Laplace transform is
linear
: if
f
and
g
are any signals, and
a
is any
scalar, we have
(af
aF,
(f
g
i.e.
, homogeneity & superposition hold example:
3 δ
(t
te
(δ
(t
(e
t)
s^
3 s
s^
The Laplace transform
the Laplace transform is
one-to-one
: if
(f
(g
then
f
g
(well, almost; see below)^ •
determines
f
inverse Laplace transform
−
1
is well defined
(not easy to show) example
(previous page):
−
3 s
s^
δ(
t)
te
in other words, the
only
function
f
such that
F
(s
3 s
s^
is
f
(t
δ(
t)
te
The Laplace transform
in principle we can recover
f
from
via
f^
(t
(^12) πj
σ+
j∞ σ−
j∞
(s
)e
st
ds
where
σ
is large enough that
(s
is defined for
s^
σ
surprisingly, this formula isn’t really useful! The Laplace transform
define signal
g
by
g
(t
f
(at
), where
a >
; then
(s
/a
(s/a
makes sense: times are scaled by
a
, frequencies by
/a
let’s check: G
(s
∞ 0
f^ (
at
)e
−
st
dt
/a
∞ 0
f^ (
τ^ )
−e (s/a
)τ
dτ
/a
(s/a
where
τ
at
example:
(e
t) = 1
s^
so
(e
at
/a
(s/a
s^
a
The Laplace transform
let
f
be a signal and
; define the signal
g
as
g(
t) =
t < T
f^ (
t^ −
t^
(g
is
f
, delayed by
seconds & ‘zero-padded’ up to
ag replacements
t
t^
t^
=
T
f^ (
t)
g(
t)
The Laplace transform
then we have
(s
e
−
sT
(s
derivation:
(s
∞ 0
− e
st
g(
t)
dt
∞ T
− e
st
f^ (
t^ −
dt
∞ 0
− e
s(
τ^ +
T^ )
f^
(τ
dτ
−e
sT
(s
The Laplace transform
if signal
f
is continuous at
t
, then
(f
sF
(s
f
time-domain differentiation becomes multiplication by frequencyvariable
s
(as with phasors)
plus
a term that includes initial condition (
i.e.
f^ (0)
higher-order derivatives: applying derivative formula twice yields
(f
sL
(f
f
s(
sF
(s
f
f
(^2) s
(s
sf
f
similar formulas hold for
(f
(k
The Laplace transform
examples^ •
f
(t
e
t, so
f
t) =
e
t^
and^ L
(f
(f
s^
using the formula,
(f
s
s^
, which is the same
sin
ωt
(^1) ω
d dt^
cos
ωt
, so
(sin
ωt
(^1) ω
s^
s (^2) s
ω
2
ω (^2) s
ω
2
f^
is unit ramp, so
f
′^ is unit step^ L
(f
s
1 2 s
/s
The Laplace transform