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Livros e Apostilas
Tipologia: Notas de estudo
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James Ward Brown Professor of Mathematics The University of Michigan-Dearborn
Rue1 V. Churchill Late Professor of Mathematics The University of Michigan
Higher Education
Boston Burr Ridge, tL Dubuque, lA Madison, WI New York San Francisco St. Louis Bangkok Bogota Caracas Kuala Lumpur Lisbon London Madrid Mexico City Milan Montreal New Delhi Santiago Seoul Singapore Sydney Taipei Toronto
function; and the sections on trigonometric and hyberbolic functions are now closer to the ones on their inverses. Encouraged by comments from users of the book in the past several years, we have brought some important material out of the exercises and into the text. Examples of this are the treatment of isolated zeros of analytic functions in Chap. 6 and the discussion of integration along indented paths in Chap. 7. The Jirst objective of the book is to develop those parts of the theory which are prominent in applications of the subject. The second objective is to furnish an introduction to applications of residues and conformal mapping. Special emphasis is given to the use of conformal mapping in solving boundary value problems that arise in studies of heat conduction, electrostatic potential, and fluid flow. Hence the
Boundary Value Problems" and Rue1 V. Churchill's "Operational Mathematics," where other classical methods for solving boundary value problems in partial differential equations are developed. The latter book also contains further applications of residues in connection with Laplace transforms.
students majoring in mathematics, engineering, or one of the physical sciences. Before taking the course, the students have completed at least a three-term calculus sequence, a first course in ordinary differential equations, and sometimes a term of advanced
footnotes referring to texts that give proofs and discussions of the more delicate results from calculus that are occasionally needed. Some of the material in the book need not be covered in lectures and can be left for students to read on their own. If mapping by elementary functions and applications of conformal mapping are desired earlier in the course, one can skip to Chapters 8, 9, and 10 immediately after Chapter 3 on elementary functions.
examples and exercises illustrating those results. A bibliography of other books, many of which are more advanced, is provided in Appendix 1. A table of conformal transformations useful in applications appears in Appendix 2. In the preparation of this edition, continual interest and support has been provided
include Jacqueline R. Brown, Ronald P. Morash, Margret H. Hoft, Sandra M. Weber,
at McGraw-Hill Higher Education.
James Ward Brown
COMPLEX VARIABLES AND APPLICATIONS
C H A P T E R
COMPLEX NUMBERS
In this chapter, we survey the algebraic and geometric structure of the complex number system. We assume various corresponding properties of real numbers to be known.
1. SUMS AND PRODUCTS Complex numbers can be defined as ordered pairs (x, y) of real numbers that are to be interpreted as points in the complex plane, with rectangular coordinates x and y, just as real numbers x are thought of as points on the real line. When real numbers
correspond to points on the y axis and are called pure imaginary numbers. The y axis is, then, referred to as the imaginary axis. It is customary to denote a complex number (x, y) by z, so that
The real numbers x and y are, moreover, known as the real and imaginary parts of z, respectively; and we write
l h o complex numbers zl = ( x l , yl) and z2 = (x2, y2) are equal whenever they have the same real parts and the same imaginary parts. Thus the statement zl = means
The sum zl + zz and the product zlz2 of two complex numbers zl = (xl, yl) and 22 = (x2, y2) are defined as follows:
Note that the operations defined by equations (3) and (4) become the usual operations of addition and multiplication when restricted to the real numbers:
The complex number system is, therefore, a natural extension of the real number system. Any complex number z = (x, y) can be written z = (x, 0) + (0, y), and it is easy to see that (0, l)(y, 0) = (0, y). Hence
and, if we think of a real number as either x or (x, 0) and let i denote the imaginary number (0, 1 ) (see Fig. I), it is clear that*
Also, with the convention z2 = zz, z3 = zz2, etc,, we find that
i (^2) = (0, l)(O, 1) = (-1, O),
i = (0, 1)
In view of expression (5), definitions (3) and (4) become
*In electrical engineering, the letter j is used instead of i
(Exercise 8) - (i y ) = (-i) y = i (- y ) .Additive inverses are used to define subtraction:
SO if z l = (xl, yl) and z2 = ( ~ 2 ,~ 2 then) ~
u and v must satisfy the pair
of linear simultaneous equations; and simple computation yields the unique solution
So the multiplicative inverse of z = ( x , y) is
The inverse z-' is not defined when z = 0. In fact, z = 0 means that x2 + y2 = 0; and this is not permitted in expression (8).
EXERCf SES
1. Verify that (a) i - 1 - i - 2 (b) (2, -3)(-2, 1)=(-1,8); 2. Show that (a)Re(iz)=-Irnz; (b)Im(iz)=ReZ. 3. Show that (1 + z ) ~ = 1 + 2z + z2. 4. Verify that each of the two numbers z = 1 & i satisfies the equation z2 - 22 + 2 = 0. S. Prove that multiplicationis commutative, as stated in the second of equations (I), Sec. 2.
SEC. 3 FURTHERPROPERTIES 5
and then solving a pair of simultaneous equations in x and y. Suggestion: Use the fact that no real number x satisfies the given equation to show
3. FURTHER PROPERTIES
In this section, we mention a number of other algebraic properties of addition and multiplication of complex numbers that follow from the ones already described in
to real numbers, the reader can easily pass to Sec. 4 without serious disruption. We begin with the observation that the existence of multiplicative inverses enables us to show that ifa product zlz2 is zero, then s o is at least one of the factors zl and
22. For suppose that t l z z = 0 and zl# 0. The inverse 'z; exists; and, according to the definition of multiplication, any complex number times zero is zero. Hence
That is, if zlz2 = 0, either z1 = 0 or zz = 0; or possibly both zl and z2 equal zero. Another way to state this result is that iftwo complex numbers zl and z2 are nonzero, then so is their product z lz2. Division by a nonzero complex number is defined as follows:
If z 1 = (xl, y l ) and 22 = (xZ, y2), equation (1) here and expression (8) in Sec. 2 tell us that
SEC. 3 EXERCISES 7
EXAMPLE. Computations such as the following are now justified:
Finally, we note that the binomial formula involving real numbers remains valid
where
n! (;) = k! ( n - k )!
( k = O , 1 , 2 ,... , n )
and where it is agreed that O! = 1. The proof, by mathematical induction, is left as an exercise.
EXERCISES
Ans. (a) - 2 / 5 ; ( b - 1 ; (c) -4.
l/z
it.
8. Use mathematical induction to verify the binomial formula (9) in Sec. 3. More precisely, note first that the formula is true when n = 1. Then, assuming that it is valid when n = rn where m denotes any positive integer, show that it must hold when n = m + 1. 4. MODULI
It is natural to associate any nonzero complex number z = x + iy with the directed line segment, or vector, from the origin to the point (x, y) that represents z (Sec. 1) in the complex plane. In fact, we often refer to z as the point z or the vector z. In Fig. 2 the numbers z = x + iy and -2 + i are displayed graphically as both points and radius vectors.
I -2 X FIGURE 2
According to the definition of the sum of two complex numbers z l = x l + iyl and 22 = x2 + iy2, the number zl + z2 corresponds to the point ( x l + x2, y1 + y2). It also corresponds to a vector with those coordinates as its components. Hence z l + z
corresponds to the sum of the vectors for z l and -22 (Fig. 4).
Although the product of two complex numbers z l and 22 is itself a complex number represented by a vector, that vector lies in the same plane as the vectors for z 1 and 22. Evidently, then, this product is neither the scalar nor the vector product used in ordinary vector analysis. The vector interpretation of complex numbers is especially helpful in extending the concept of absolute values of real numbers to the complex plane. The modulus, or absolute value, of a complex number z = x + iy is defined as the nonnegative real
CHAP. I
Thus
(3) R e z s 1 R e z l ~ l z l and^ I m z s 1 I m z l S l z l +
We turn now to the triangle inequality, which provides an upper bound for the modulus of the sum of two complex numbers z l and 22:
This important inequality is geometrically evident in Fig. 3, since it is merely a statement that the length of one side of a triangle is less than or equal to the sum of the lengths of the other two sides. We can also see from Fig. 3 that inequality (4)
derivation is given in Exercise 16, Sec. 5. An immediate consequence of the triangle inequality is the fact that
To derive inequality (5), we write
which means that
This is inequality (5) when lz 1 2 1 z21. If 1 z 11 < 1 z2 1, we need only interchange z 1 and 22 in inequality ( 6 ) to get
which is the desired result. Inequality (5) tells us, of course, that the length of one side of a triangle is greater than or equal to the difference of the lengths of the other two sides. Because I - 221 = 1z21, one can replace z2 by -z2 in inequalities ( 4 ) and (5) to summarize these results in a particularly useful form:
EXAMPLE 3. If a point z lies on the unit circle 12) = 1 about the origin, then
and
The triangle inequality (4) can be generalized by means of mathematical induc- tion to sums involving any finite number of terms:
To give details of the induction proof here, we note that when n = 2, inequality (9) is just inequality (4). Furthermore, if inequality (9) is assumed to be valid when n = m, it must also hold when n = m + 1 since, by inequality (4),
EXERCISES
1. Locate the numbers zl+ z2 and zl - z2 vectorially when
(c) z1 = (-3, l), zz = (1,4); ( d ) zl = X I + iyl,^22 = X I^ -^ i ~ 1.
2. Verify inequalities (3), Sec. 4, involving Re z , Im z, and lzl. 3. verify that &lzl 2 IRezl + IImzl. Suggestion: Reduce this inequality to (Ix I - 1 ~ 1 2 ) ~ 0.
argument that (a) 1 z - 4 i I + lz + 4i I = 10 represents an ellipse whose foci are (0, f4); (b) [z - 11 = [ Z + i 1 represents the line through the origin whose slope is - 1.
5. COMPLEX CONJUGATES The complex conjugate, or simply the conjugate, of a complex number z = x + iy is
The number 'Z is represented by the point (x, -y), which is the reflection in the real
Z = Z and l? t = l z l
for all z. If z l = xl + iyl and 22 = x2 + i ~ 2 , then
zl + z2 = ( x l + x2) - i(yl + y2) = ( X I - i ~ i ) + ( ~ 2 - i~2).