salim-avatar

When I am solving for the force of gravity between two objects...(con't.)?

I would take the mass of two objects in kilograms (what do I use if they are less than that) multiply them with another then divide by the distance squared, between the two (do I factor in other forces of gravity as well or is that already assumed) and multiply by 6.67x ten to the negative 11th to...get something in newtons? Yet isn't the equation for newtons F = M * A... Is this Just a lack of understanding because I have so many questions? I mean kilograms is a relative term so is there a ratio for the change of it's value considering anywhere outside of earths gravitational field or would I just put in the distance for that ratio....aghhhhhhh. Please help me...Don't send me to wikipedia either.
over 13 years ago
0%

6 replies

over 13 years ago
kaety-avatar
"F= ma is not relevant at this point. F = GMm / R^2 is discovered to be the gravitational force between any two bodies. There ARE no other forces of gravity. This is the amount of attraction between these two bodies irrespective of any other gravitational forces that also exist. kilograms is not a relative term. The constant G = 6.67 * 10 ^ -11 is found experimentally. The value is only true if you use masses measured in kg and distances measured in m. If you wished to use other units then you would also need to establish the appropriate constant for those other units. And that is too much like hard work. Quite needlessly too. Even if the masses are far smaller than 1 kg the masses must still be measured in kg to use the constant specified. NOW let us add in F = ma but F ALSO = GMm/ R^2 so ma = GMm/ R^2 a = GM/ R^2 i.e the acceleration caused by gravity has this value. We normally use the symbol ""g"" for this special acceleration. But it still represents an acceleration anyway."
about 13 years ago
pamelaaaa-avatar
Utilized in talk to cut back your force out of an declaration or even view, or even with good grace suggest as well as turn down one thing